Session 27. Probabilistic and Extremal Combinatorics |
Hamilton saturated hypergraphs of essentially minimum size |
Andrzej Żak, AGH University of Science and Technology, Poland |
The talk is based on the joint work with Andrzej Ruciński |
For \(1\leq \ell< k\), an \(\ell\)-overlapping cycle is a \(k\)-uniform hypergraph in which, for some
cyclic vertex ordering, every edge consists of \(k\) consecutive vertices and every two consecutive
edges share exactly \(\ell\) vertices. A \(k\)-uniform hypergraph \(H\) is \(\ell\)-Hamiltonian saturated if \(H\) does not contain an \(\ell\)-overlapping Hamiltonian cycle but every hypergraph obtained from \(H\) by adding one more edge does contain such a cycle. Let sat\((n,k,\ell)\) be the smallest number of edges in an \(\ell\)-Hamiltonian saturated \(k\)-uniform hypergraph on \(n\) vertices. In the case of graphs Clark and Entringer [1] proved in 1983 that sat\((n,2,1)=\lceil \tfrac{3n}2\rceil\).
For hypergraphs with \(k\ge3\) it seems to be quite hard to obtain such precise results. Therefore,
the emphasis is put on the order of magnitude of sat\((n,k,\ell)\).
We proved that for \(k\geq 3\) and \(\ell=1\) as well as for all \(0.8k\leq \ell\leq k-1\)
\begin{align}
{\rm sat}(n,k,\ell)=\Theta(n^{\ell}),
\end{align}
see [2,3]. Recently, we have got also some partial results:
sat\((n,k,\ell)=O(n^{(k+\ell)/2})\) and, in the smallest open case, sat\((n,4,2)=O(n^{14/5})\). |
References
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